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hi,

 i am using ZipoutputStream to create a zip file.

Its creating zip file correctly. & extracting & opening in my machine.

but when i sent that file to other machine in network, it is not opening. it shows the size of the file & other thing. but when we open the file

it is empty.

Is there any issue on the file path??? its creating whole path of the actual file system in the zip. ie. c:\test\zipfiles\ then the file.

Any idea what is the problem

Hi,

paths should not include windows device names and absolute paths.  They can exist in zip archives but some programs are unable handle these non-standard paths.

Paths are supposedt be relative paths with unix '/' separators not windows '\'  style.

What are you trying to extract the files with on this other network machine?

Hi,

I've the same problem now.
On my machine (WinAce) anything is fine but on any other machine in the network it do not work (WinRAR or Windows-Only Zip).
I understand the problem with the slash but how to solve this to make it more compatible?
Is there a flag for when zipping?

Thanks,

Andre

Thanks for the reply.

i am trying to use windows compressed folder on the other machine.

also, its not working with windows compressed folder on my machine.

Is there any way to create zip on the root, without any path??

Regards,

Pragnesh 

I think I found a way to solve this problem.

Please have a look at the manual and search for CleanName and ZipNameTransform Class...

Regards,

Andre

hi,

help file is not opening on my machine.

can you share code snippet??

thanks

Pragnesh 

Have a look here

http://www.componentspot.com/doccenter/SharpZipLib/icsharpcode.sharpziplib.zip.zipentry.cleanname_overload_1.html

thanks

It works fine.

I used following code.

zpFile.Add(fileName.ToString());