SharpDevelop Community

Hi,

i have an application where i need to make a zip file from file contents stored in SQL server database. i am getting each file in bytes as per the below code

s.SetLevel(0); // 0 - store only to 9 - means best compression

bytes = Utility.GetBytes(cvReader, 4, 3);

ZipEntry entry = new ZipEntry(file);

//Copy the bytes to the output stream

// Something like this should work I believe.

// Each entry should have a unique name

ZipEntry entry = new ZipEntry(cvReader.Current.Name); // How to identify each cv?

s.PutNextEntry(entry);

I am wondering how to do the same thing as the original poster is. I know how to do the actual zipping in memory but I do not know how (or if it is possible) to add files, in the form of byte array, to the zip in memory.

From what I understand, the process is as follows:

1. Create a ZipOutputStream.
2. Create a ZipEntry and pass it the path of the file to add.
3. Call ZipOutputStream.PutNextEntry(ZipEntry).
4. Close streams, etc.

My question is this: Can I somehow create a ZipEntry with an array of bytes, instead of a file path? Otherwise, I cannot see how you could do this in memory. I tried out the ZipOutputStream.Read() method which takes in an array of bytes but I receive a "DeflaterOutputStream Read not supported" exception.

I am using assembly version 0.85.5.452 of the ICSharpCode.SharpZipLib library with .NET Framework 3.5.

EDIT: Found the solution (from a reply in another thread). Basically the ZipEntry is created with the filename as the string (which I thought needed to be an actual path to the file) and the MemoryStream's WriteTo() method is used and the ZipOutputStream is sent as an argument:

ZipEntry zipEntry = new ZipEntry("filename");
zipOutputStream.PutNextEntry(entry);
fileMemoryStream.WriteTo(zos)