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Im trying to use ICSharpCode.SharpZi pLib.Zip to compress a file that is 12 Gb in size. I used the following console application to compress initially.

using System;
using System.IO;

using ICSharpCode.SharpZipLib.Zip;

class MainClass
{
  public static void Main(string[ args)
  {
       string[ aFilenames = Directory.GetFiles("Y:\\huge");
   
      ZipOutputStream s = new ZipOutputStream(File.Create("Y:\\zipfile.zip"));
   
    s.SetLevel(5);
   
    for (int i=0; i < aFilenames.Length; i++)
    {
      FileStream fs = File.OpenRead(aFilenames[i]);
     
           byte[ buffer = new byte[fs.Length];
      fs.Read(buffer, 0, buffer.Length);

        ZipEntry entry = new ZipEntry(aFilenames[i]);
      s.PutNextEntry(entry);
      s.Write(buffer, 0, buffer.Length);
    }
   
    s.Finish();
    s.Close();
  }
}
 I got an error msg  at this line: byte[ buffer = new byte[fs.Length]---Arithmatic overflow exception. Hence I stored the huge value in long and i did explicit downcasting to byte as shown below

            long flength = fs.Length;
            byte length=(byte)flength;

            byte[ buffer = new byte[length];
            fs.Read(buffer, 0, buffer.Length);

But when i run the code I see that byte length value gets calculated as 0 instead of  13,205,999,104 which is a long value. I'm trying to zip a file as big as 12 GB or 13,205,999,104 bytes. Can any one suggest how this can be fixed?

Hi Cindy,

Its bad practise to allocate buffers the length of files as they can be very large.  Use a fixed size buffer and copy the contents in a loop.The library has a StreamUtils class that supports this so you can copy streams as shown below.

                buffer=new byte[4096];
                StreamUtils.Copy(stream, outputStream, buffer);

hth, -jr-